64x^2-32x-5=0

Solution for 64x^2-32x-5=0 equation:

64x^2-32x-5=0

a = 64; b = -32; c = -5;
Δ = b2-4ac
Δ = -322-4·64·(-5)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-48}{2*64}=\frac{-16}{128}
=-1/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+48}{2*64}=\frac{80}{128}
=5/8
$